solutions (`a la Calder�on [1]) introduced in [5] and some arguments already used by the author in [6.8) The first inequality in (3.2) follows easily because |Z1,(t, , x)| 1 e q1 T M1 and, as the same arguments,s] - A2[f,s] (t, , )(t, , ) ddt = T 0 ( � ())+ R1,,s(t, , ) - R2,,s(t, , ) (t, , ) ddt, (4.8) 14 #12;where